Department of Electrical and Computer Engineering
University of Texas at Austin
EE 379K, Fall 2000
Y. N. Patt, Instructor
TAs: Kathy Buchheit, Laura Funderburg, Chandresh Jain, Onur Mutlu, Danny Nold, Kameswar Subramanian, Francis Tseng, Brian Ward

Programming Assignment 4
Due: November 21, 2000 11:59 PM

Integer to Floating-Point Conversion

Problem Statement

In this program we explore how data types can be converted to one another. We ask you to implement a program in LC-2 assembly language that converts an integer from its 2's complement representation into its corresponding floating-point representation and outputs the floating-point equivalent of the 2's complement integer onto the screen. As the LC-2 does not have a defined floating-point standard, we will first define a 16-bit floating-point format.

16-Bit Floating-Point Format Definition

By now, you should be familiar with the 32-bit IEEE standard floating-point format. If you want to refresh your memory, take a look at section 2.7.1 of the textbook. The word-size of LC-2 is 16 bits. Therefore, to make things easier we will define a 16-bit floating-point format to be used in this program. This format consists of 1 sign bit, 6 bits reserved for the exponent, and 9 bits reserved for the fraction. The format of a floating-point number looks like the following:
15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0
s exponent fraction

The bias of the above definition is 31, and therefore any floating-point number in the above format evaluates to

(-1)S x 2(exponent - 31) x 1.fraction

Program Details

Your program should perform the following steps:

  1. Take a 2's complement number stored in memory location x3100, convert the number into the floating-point representation specified above, and store the converted result into memory location x3101. Note that you will have to set memory location x3100 with a 2's complement value before you execute your program.
  2. Output the 16-bit floating-point representation in 0's and 1's onto the screen.

Sample Output

For example, suppose memory location x3100 contains the value 0000000000011001 (decimal 25) before the program starts. After the program executes, memory location x3101 should contain the value 0100011100100000 (floating-point 25). The program should also output the following:

FP representation is 0100011100100000
Suppose memory location x3100 contains the value 1000000000000000 (decimal -32768) before the program starts. After the program executes, memory location x3101 should contain the value 1101110000000000 (floating-point -32768). The program should also output the following:
FP representation is 1101110000000000


  1. You are not required to perform bounds checking. Note that the 2's complement number in memory location x3100 contains a number in the range -32768 to 32767.
  2. Store the result of the floating-point conversion in memory location x3101.
  3. Make sure you follow the output conventions (i.e. the output should be exactly the same as the sample output shown above).
  4. Important: When the fraction field is not enough to accurately represent the initial integer, truncate the fraction field. The floating-point representation should be as close as possible in value to the initial integer. For example, if memory location x3100 contains the 2's complement representation of the integer 4147, the floating-point representation of 4147 should be 0101011000000110. Note that if you calculate what floating-point 0101011000000110 corresponds to, you will get the value of 4144. This is due to the fact that, to be precisely represented in the above floating-point format, 4147 needs a fraction field of at least 12 bits. But our floating-point format has a fraction field of 9 bits. Therefore the least significant three bits in the fraction of 4147 should be discarded. This is called truncation.

Writing and submitting your program